Can you find the smallest positive number that is divisible by 15 that consists ONLY of ones and zeroes (e.g. 10, 11, 100, etc.)? Note that you don't need a calculator to solve the problem
ANSWER: 1,110.
EXPLANATION: Because the number is divisible by 15, it must also be divisible by 3 and 5 (since 15 is divisible by 3 and 5). The sum of the digits of a number that is divisible by 3 must equal 3 (this is a clever little math trick/shortcut). The number therefore must contain three ones, six ones, etc. Since the number is divisible by 5, we know that it must end in a 0 (numbers that are divisible by 5 end in a 0 or a 5). The first number that contains three ones and ends in a 0 is 1,110
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